19k^2-7=2729

Solution for 19k^2-7=2729 equation:

19k^2-7=2729

We move all terms to the left:

19k^2-7-(2729)=0

We add all the numbers together, and all the variables

19k^2-2736=0

a = 19; b = 0; c = -2736;
Δ = b2-4ac
Δ = 02-4·19·(-2736)
Δ = 207936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{207936}=456$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-456}{2*19}=\frac{-456}{38}
=-12
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+456}{2*19}=\frac{456}{38}
=12
$